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Before taking a closer look at how torque, work, and power are involved in
an engine, we need formal definitions of work and power. When we think of the
words, “work” and “power”, many different meanings may
come to mind. Work is often thought of as physical labor or something we get
paid to do. Common meanings for power include the amount of energy something
can produce, the electricity that we get out of electrical sockets, or a synonym
for strength. According to physics, work and power have specific definitions,
and we’re about to learn what those are.
When a force acts to move an object, work is done.
This is written as
Work = Force · Distance force acts
When you push something, how much work you do on it depends both on how hard you push it and how far you push it. In the Imperial system, work is measured in foot pounds (ft lb). The equivalent unit in the SI system is the Newton meter (N m), also known as the Joule (J). This is named after James Prescott Joule, a scientist who lived in the 1800’s and made important discoveries in the field of thermodynamics, or the study of heat, work, and other forms of energy.
Example 1: (Using SI units) Solution: Work = Force · Distance In pulling the hovercraft along the sandbar, you performed 250 J [184.4 ft lb] of work on the hovercraft. 
Example 2: (Using Imperial units) Solution: Work = Force · Distance It will take 180 ft lb [244 J] of work to lift the hovercraft onto the horses. 
Remember that torque can be thought of as a turning or twisting force. When we talk about work done by a torque, we multiply the torque by how much it turns, or the angle it rotates through.
Work = Torque · Angle torque acts through
To turn an object, you exert a torque on it. How much it turns is given by
the angle it turns through. For example, if you tighten a screw so that the
screw twists one full revolution (360°), you exerted a torque on that screw
through an angle of 360°.
Before we can do some examples, we need to know what units the angles are in.
We are most familiar with angles in terms of degrees. When doing calculations
with angles, however, we need to use a unit called radians.
1 radian is equal to about 57.3°. Why would anyone want to make a new unit
for angles which is equal to 57.3°? Look at the figure of the circle. It
shows both an angle of 1° and of 1 rad (short for radian). You can see that
the angles cut out triangular pieces of the circle. The length of the portion
of the circle contained in that triangular section is called the arc
length. It turns out when the angle is 1 rad, the arc length is
equal to the radius of the circle! Another interesting fact is that 1 full revolution
(360°) is equal to 2 radians.
Half of a revolution (180°) is therefore equal to
radians. Remember that is equal
to 22/7.
Example 3: Solution: Work = Torque · Angle Turning the propeller 3 revolutions will require 188.5 ft lb [255.6 N m] of work. 
Now we need a way to define power. Power is the rate at which work is performed, or the amount of work done per unit time.
Power = Work ÷ Time
Go back to the example where you pull the hovercraft along the sandbar. You could take 10 seconds to pull the craft that far, or you could pull really slowly and take 10 minutes. Either way, you’re still doing the same amount of work. Your power, however, is greater the faster you pull it. In the Imperial system, power is usually measured in horsepower (hp). In the metric system, Joules per second (J/s) has another name, the Watt (W). This was named after James Watt, an engineer who made important contributions to the development of the steam engine. Interestingly, James Watt invented the term horsepower. It is said that he measured a pony producing 22,000 foot pounds of work in a minute while pulling buckets of coal out of a mine. He thought that horses were about 50% more powerful than a pony, so he increased it to 33,000 foot pounds per minute, or 550 foot pounds per second. This is also equal to 746 Watts in SI units.
To get power from torque, multiply torque by the angle it acts through, then divide by the amount of time it takes. This angle per unit time is called an angular velocity. With engines, this is commonly called revolutions per minute (rpm). If we multiply torque by angular velocity, we get power. Often we know the horsepower of an engine, but want to know how much torque it can produce. We now have a simple formula for this.
Power = Torque · Angular velocity
 or 
Torque = Power ÷ Angular velocity
When doing these calculations, it is essential that all the values are in similar units. This often leads to some unit conversions to ensure they are similar.
Example 4: Solution: (2500 revolution/min) · (2 rad/revolution) ÷ (60 sec/min) = 261.8 rad/s Convert horsepower to either foot pounds per second or watts, depending on if we’re using Imperial or SI units. For this example, we’ll use Imperial units. (12.5 hp) · (550 ft lb/s / hp) = 6875 ft lb/s With power in foot pounds per second and angular velocity in radians per second, calculate the torque produced. Torque = Power ÷ Angular velocity When Discover Hover One’s engine runs at 2500 rpm, it will produce 26.3 ft lb [35.7 N m] of torque. 